New ATI Products Confirmed: The X Series Line-up
by Derek Wilson on June 1, 2004 6:00 AM EST- Posted in
- GPUs
Final Words
Even though we don't have parts in our hands yet, we are excited to test out the new 110nm parts, as well as the new mobile technology coming down the pipe this year.To sum up, click on the following link to the table that shows what ATI is announcing today, and the specs for everything.
ATI Card Table
Of course, after this first round of PCI Express graphics card releases, ATI will be slowly moving its new R4xx style architecture down through the mid-range and low end as well. It remains to be seen how NVIDIA is going to handle the mainstream market segments, but ATI is only bringing a few new enhancements to their current lineup of graphics cards today. Among the new include PCI Express support, a 110nm fab process for the X300 (which we assume to be based on the 9600 core due to its RV370 model number), and a couple of new power-saving and image quality enhancing technologies that will come to the mobile market whenever the Mobility Radeon X600 finally makes its way into a notebook near you.
Facebook
Twitter
RSS
10 Comments
View All Comments
Pumpkinierre - Tuesday, June 1, 2004 - link
Maybe 110nm is just on that limit where present technology allows the usual shrink/power reduction effect to be maintained without all the 90nm problems that really require a rethink to sort out. If that's the case it might be a good overclocker but could suffer from overvoltage or early death.quanta - Tuesday, June 1, 2004 - link
I wonder if anyone even cares about the 130nm X600 part, when they can just overclock 110nm X300 cards. But then again, die shrinks from 130nm to 90nm has given Intel a lot of trouble in the form of voltage leak and heat, I suspect X300 may not be able to run as fast as X600 without generate a lot more heat.Gholam - Tuesday, June 1, 2004 - link
Hmm, do I get it right that there won't be an 8-pipeline PCI-E Radeon? Straight from 4-pipeline X600 to 12-pipeline X800 PRO? Sounds somewhat strange... X800SE anyone?sxr7171 - Tuesday, June 1, 2004 - link
nserra - Tuesday, June 1, 2004 - link
#jcromanoNice explanation, have you used on processors too, like it would be amd 90nm athlon 64 die size?
This is much like digital camera 3mp to 5mp, it's almost the double but if you look at it, you would say it's only 30%/40% bigger. Or ati 160m transitors vs nvidia 222m. Ati is almost "big" but it has less 62m or a radeon 9600 less, funny isn't it?
Cycophant - Tuesday, June 1, 2004 - link
Small spelling mistake on the article intro:"Today, ATI fills out their new X series with three new PCI Express parts based on current __technolgoy__ that we are seeing. "
spikemike - Tuesday, June 1, 2004 - link
I don't believe blacks will look any blacker, you have to remember that the backlight is constant throughout the entire lcd. You can't control the brightness at a single pixel, so if you wanted to make blacks blacker then the whole screen would get darker, making the whites darker too, and in a very low darkness scene, you don't want to lose the black level resolution.vedin - Tuesday, June 1, 2004 - link
Darn..and I was really hoping that the X600 would be a little faster in the core and memory than the 9600XT. Say..550mhz? Honestly, I was hoping for a scaled down X800..so much for wishful thinking.jcromano - Tuesday, June 1, 2004 - link
I believe your claim that "a straight die shrink only accounts for about a 30% increase in space efficiency," found in paragraph 3 of the page titled "X300 Debuts at 110nm," may be in error.I'm not really sure what "space efficiency" is, but you make this claim in contrast to ATI's claim of a 40% increase in transistors per given area.
Assuming that the number of transistors per unit area scales inversely with the square of the (linear) process size, we have:
transistor density = k/d^2
For the old 130nm process, then,
transistor density (old value) = k/130^2.
For the new 110nm process,
transistor density (new value) = k/110^2.
The generally accepted way of presenting a percent increase or decrease is to use the old value as the denominator of the fraction. A formula such as this one would be appropriate:
(new value/old value) - 1
where the result is re-expressed as a percent, and a positive result is interpreted as an increase.
If we plug in, using k/110^2 for the new value (numerator) and k/130^2 for the old value (denominator), and cancel the k's, we get
130^2/110^2 - 1 = .39669 = 39.669%, which is admittedly lower than the 40% claimed by ATI, but close enough for me.
ducsauce - Tuesday, June 1, 2004 - link
I wonder if ATI will put out an All-in-wonder version of the x800 some time this year. The AIW 9800 pro is not going to keep up for long.